16x^2-58x-63=0

Solution for 16x^2-58x-63=0 equation:

16x^2-58x-63=0

a = 16; b = -58; c = -63;
Δ = b2-4ac
Δ = -582-4·16·(-63)
Δ = 7396
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{7396}=86$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-58)-86}{2*16}=\frac{-28}{32}
=-7/8
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-58)+86}{2*16}=\frac{144}{32}
=4+1/2
$